Optimal. Leaf size=215 \[ -\frac {(4+n) \cos (c+d x) (a+a \sin (c+d x))^n}{d (1+n) (2+n) (3+n)}-\frac {\cos (c+d x) \sin ^2(c+d x) (a+a \sin (c+d x))^n}{d (3+n)}-\frac {2^{\frac {1}{2}+n} n \left (5+3 n+n^2\right ) \cos (c+d x) \, _2F_1\left (\frac {1}{2},\frac {1}{2}-n;\frac {3}{2};\frac {1}{2} (1-\sin (c+d x))\right ) (1+\sin (c+d x))^{-\frac {1}{2}-n} (a+a \sin (c+d x))^n}{d (1+n) (2+n) (3+n)}-\frac {n \cos (c+d x) (a+a \sin (c+d x))^{1+n}}{a d \left (6+5 n+n^2\right )} \]
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Rubi [A]
time = 0.21, antiderivative size = 215, normalized size of antiderivative = 1.00, number of steps
used = 6, number of rules used = 6, integrand size = 21, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.286, Rules used = {2862, 3047,
3102, 2830, 2731, 2730} \begin {gather*} -\frac {2^{n+\frac {1}{2}} n \left (n^2+3 n+5\right ) \cos (c+d x) (\sin (c+d x)+1)^{-n-\frac {1}{2}} (a \sin (c+d x)+a)^n \, _2F_1\left (\frac {1}{2},\frac {1}{2}-n;\frac {3}{2};\frac {1}{2} (1-\sin (c+d x))\right )}{d (n+1) (n+2) (n+3)}-\frac {n \cos (c+d x) (a \sin (c+d x)+a)^{n+1}}{a d \left (n^2+5 n+6\right )}-\frac {\sin ^2(c+d x) \cos (c+d x) (a \sin (c+d x)+a)^n}{d (n+3)}-\frac {(n+4) \cos (c+d x) (a \sin (c+d x)+a)^n}{d (n+1) (n+2) (n+3)} \end {gather*}
Antiderivative was successfully verified.
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Rule 2730
Rule 2731
Rule 2830
Rule 2862
Rule 3047
Rule 3102
Rubi steps
\begin {align*} \int \sin ^3(c+d x) (a+a \sin (c+d x))^n \, dx &=-\frac {\cos (c+d x) \sin ^2(c+d x) (a+a \sin (c+d x))^n}{d (3+n)}+\frac {\int \sin (c+d x) (a+a \sin (c+d x))^n (2 a+a n \sin (c+d x)) \, dx}{a (3+n)}\\ &=-\frac {\cos (c+d x) \sin ^2(c+d x) (a+a \sin (c+d x))^n}{d (3+n)}+\frac {\int (a+a \sin (c+d x))^n \left (2 a \sin (c+d x)+a n \sin ^2(c+d x)\right ) \, dx}{a (3+n)}\\ &=-\frac {\cos (c+d x) \sin ^2(c+d x) (a+a \sin (c+d x))^n}{d (3+n)}-\frac {n \cos (c+d x) (a+a \sin (c+d x))^{1+n}}{a d \left (6+5 n+n^2\right )}+\frac {\int (a+a \sin (c+d x))^n \left (a^2 n (1+n)+a^2 (4+n) \sin (c+d x)\right ) \, dx}{a^2 (2+n) (3+n)}\\ &=-\frac {(4+n) \cos (c+d x) (a+a \sin (c+d x))^n}{d (1+n) (2+n) (3+n)}-\frac {\cos (c+d x) \sin ^2(c+d x) (a+a \sin (c+d x))^n}{d (3+n)}-\frac {n \cos (c+d x) (a+a \sin (c+d x))^{1+n}}{a d \left (6+5 n+n^2\right )}+\frac {\left (n \left (5+3 n+n^2\right )\right ) \int (a+a \sin (c+d x))^n \, dx}{(1+n) (2+n) (3+n)}\\ &=-\frac {(4+n) \cos (c+d x) (a+a \sin (c+d x))^n}{d (1+n) (2+n) (3+n)}-\frac {\cos (c+d x) \sin ^2(c+d x) (a+a \sin (c+d x))^n}{d (3+n)}-\frac {n \cos (c+d x) (a+a \sin (c+d x))^{1+n}}{a d \left (6+5 n+n^2\right )}+\frac {\left (n \left (5+3 n+n^2\right ) (1+\sin (c+d x))^{-n} (a+a \sin (c+d x))^n\right ) \int (1+\sin (c+d x))^n \, dx}{(1+n) (2+n) (3+n)}\\ &=-\frac {(4+n) \cos (c+d x) (a+a \sin (c+d x))^n}{d (1+n) (2+n) (3+n)}-\frac {\cos (c+d x) \sin ^2(c+d x) (a+a \sin (c+d x))^n}{d (3+n)}-\frac {2^{\frac {1}{2}+n} n \left (5+3 n+n^2\right ) \cos (c+d x) \, _2F_1\left (\frac {1}{2},\frac {1}{2}-n;\frac {3}{2};\frac {1}{2} (1-\sin (c+d x))\right ) (1+\sin (c+d x))^{-\frac {1}{2}-n} (a+a \sin (c+d x))^n}{d (1+n) (2+n) (3+n)}-\frac {n \cos (c+d x) (a+a \sin (c+d x))^{1+n}}{a d \left (6+5 n+n^2\right )}\\ \end {align*}
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Mathematica [C] Result contains higher order function than in optimal. Order 6 vs. order 5 in
optimal.
time = 120.76, size = 59941, normalized size = 278.80 \begin {gather*} \text {Result too large to show} \end {gather*}
Warning: Unable to verify antiderivative.
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Maple [F]
time = 0.86, size = 0, normalized size = 0.00 \[\int \left (\sin ^{3}\left (d x +c \right )\right ) \left (a +a \sin \left (d x +c \right )\right )^{n}\, dx\]
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int {\sin \left (c+d\,x\right )}^3\,{\left (a+a\,\sin \left (c+d\,x\right )\right )}^n \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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